Exercise 1
A fixed amount of a gas occupies a volume of 1L and exerts a pressure of 400 kPa on the walls of its container. What would be the pressure exerted by the gas if it is completely transferred into a new container having a volume of 3 liters (assuming the temperature and quantity of gas remains constant)?
Given,
Initial volume (V1) = 1L
Initial pressure (P1) = 400 kPa
Final volume (V2) = 3L
As per Boyle’s law, P1V1 = P2V2 ⇒ P2 = (P1V1)/V2
P2 = (1L * 400 kPa)/3L = 133.33 kPa
Therefore, the gas exerts a pressure of 133.33 kPa on the walls of the 3-liter container.
Exercise 2
A gas exerts a pressure of 3 kPa on the walls of container 1. When container 1 is emptied into a 10-liter container, the pressure exerted by the gas increases to 6 kPa. Find the volume of container 1. Assume that the temperature and quantity of the gas remain constant.
Given,
Initial pressure, P1 = 3kPa
Final pressure, P2 = 6kPa
Final volume, V2 = 10L
According to Boyle’s law, V1 = (P2V2)/P1
V1 = (6 kPa * 10 L)/3 kPa = 20 L
Therefore, the volume of container 1 is 20 L.